15x^2-145x+300=0

Solution for 15x^2-145x+300=0 equation:

15x^2-145x+300=0

a = 15; b = -145; c = +300;
Δ = b2-4ac
Δ = -1452-4·15·300
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3025}=55$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-145)-55}{2*15}=\frac{90}{30}
=3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-145)+55}{2*15}=\frac{200}{30}
=6+2/3
$